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SCERT Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.3
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SCERT Assam Solutions for Class 7 Maths Chapter 8 Comparing Quantities Exercise 8.3. Comparing Quantities in English and Assamese Medium modified and updated for academic year 2024-25. All the question-answers and solutions are revised on the basis of new syllabus and latest SEBA SCERT textbooks issued for curriculum 2024-25.
All the question answers with solutions are done according to latest SCERT Assam Books for 2024-25.
Exercise: 8.3
1. Find the profit or loss in the following transactions. Also find profit per cent or loss percent in each case.
(লেনদেন বোৰত কিমান লাভ বা লোকচান হৈছে কোৱা। প্ৰত্যেক ক্ষেত্ৰতে লাভ বা লোকচানৰ শতাংশ উলিওৱা ।)
a) A ball bought for ₹ 300 and sold for ₹ 450.
(এটা বল তিনিশ টকাত কিনি 450 টকা বেছিলে।)
Solution:
Given, Cost price =₹ 300
Selling price = ₹ 450
We know that,
Profit = Selling price – Cost
= ₹ 450 – ₹ 300
= ₹ 150
Now, percentage of Profit,
`=\frac{Profit}{Cost}\times100`
`=\frac{150}{300}\times100`
`=50%`
Answer: Profit = ₹ 150 and percentage of profit = 50%
b) A TV bought for ₹10,000 and sold for ₹15,500.
(এটা TV 10,000 টকাত কিনিলে আৰু 15,500 টকাত বেছিলে ।)
Solution:
Given,
Cost price =₹ 10,000
Selling price = ₹ 15,500
We know that,
Profit = Selling price – Cost
= ₹ 15,500 – ₹ 10,000
= ₹ 5,500
Now, percentage of Profit,
`=\frac{Profit}{Cost}\times100`
`=\frac{5,500}{10,000}\times100`
`=55%`
Answer: Profit= Rs. 5,500 and percentage of profit = 55%
c) A cupboard bought for 5,000 and sold for 3,500.
(এটা আলমাৰি 5,000 টকাত কিনিলে আৰু 3,500 টকাত বেছিলে।)
Solution:
Given,
Cost price =₹ 5,000
Selling price = ₹ 3,500
We know that,
Loss = Cost price - Selling price
= ₹ 5,000 – ₹ 3,500
= ₹ 1,500
Now, percentage of Loss,
`=\frac{Loss}{Cost}\times100`
`=\frac{1500}{5000}\times100`
`=30%`
Answer: Loss= ₹ 1500 and percentage of Loss = 30%
d) A shirt bought for ₹ 400 and sold for ₹280.
(এটা চোলা 400 কিনিলে আৰু 280 টকাত বেছিলে।)
Solution:
Given,
Cost price =₹ 400
Selling price = ₹ 280
We know that,
Loss = Cost price - Selling price
= ₹ 400 – ₹ 280
= ₹ 120
Now, percentage of Loss,
`=\frac{Loss}{Cost}\times100`
`=\frac{120}{400}\times100`
`=30%`
Answer: Loss = ₹120 and percentage of Loss = 30%
2. Population of an area decreases from 45,000 to 42,000. Calculate percentage of decrease.
(এটা অঞ্চলৰ জনসংখ্যা 45,000 ৰ পৰা 42,000 হ্ৰাস পালে । হ্ৰাসৰ শতকৰা উলিওৱা।)
Solution:
Given,
Population of an area decreases from 45,000 to 42,000
Now,
Population of decreases = 45,000 - 42,000
= 3,000
And,
Percentage of Decreases`=\frac{3,000}{45,000}\times100`
`=\frac{20}{3}`
`=6\frac{2}{3}%`
3. A book bought for ₹ 250 and sold for ₹ 190. What is the profit or loss in percentage?
(এখন কিতাপ ২৫০ কিনি ১৯০ টকাত বিক্ৰী কৰিলে । তেওঁৰ লাভ বা লোকচানৰ শতকৰা হাৰ কিমান?)
Solution:
Given,
Cost Price = ₹250
Selling price = ₹ 190
We know that,
Loss = Cost price - Selling price
= ₹ 250 – ₹ 190
= ₹ 60
Loss percentage `=\frac{Loss}{Cost}\times100%`
Loss percentage `=\frac{60}{250}\times100%`
`= 24%`
The loss percentage is 24%
4. Rohan has bought a TV for ₹ 10,500 and sold if at a profit of 30%. Calculate the selling price of the TV.
(ৰোহানে এটা TV 10,500 কিনিলে আৰু 30% লাভত বেছিলে । TV টোৰ দাম নিৰ্নয় কৰা।)
Solution:
Given,
Cost Price = ₹10,500
Profit % = 30
We know that,
Selling Price = Cost Price`\times\left(1+\frac{Profit%}{100}\right)`
= 10,500`\times\left(1+\frac{30}{100}\right)`
= 10,500`\times1.3`
= 13,650
The selling price of the TV is ₹13,650.
5. Sumona has bought a car for ₹ 2,50,000 and sold for ₹ 2,30,000. What is the loss or profit in percentage?
(সুমনাই এখন গাড়ী 2,50,000 টকাত কিনি 2,30,000 টকাত বিক্ৰী কৰিলে । তেওঁৰ লাভ বা লোকচানৰ শতকৰা হাৰ কিমান ?)
Solution:
Given,
Cost Price = ₹2,50,000
Selling Price = ₹2,30,000
We know that,
Loss = Cost price - Selling price
= ₹ 2,50,000 – ₹ 2,30,000
= ₹ 20,000
Now,
Loss Percentage`=\left(\frac{Loss}{CostPrice}\right)\times100`
`=\frac{20,000}{2,50,000}\times100`
`=8%`
6. A motor cycle has been sold for ₹ 23,000 at a profit of 15%. What is the cost price of the motor cycle?
(15% লাভ কৰি এখন মটৰ চাইকেল 23,000 টকাত বেছিলে। মটৰ চাইকেল খনৰ দাম কিমান ?)
Solution:
Given,
Selling Price = ₹23,000
Profit % = 15
We know that,
Cost Price`=\left(\frac{S. P.}{1+\frac{Profit%}{100}}\right)`
`=\frac{23,000}{1.15}`
`= 20,000`
The cost price of the motorcycle is ₹20,000.
7. Ratan has bought an almirah for ₹ 6,250 and sold at a loss of 24%. What is the selling price of the almirah?
(ৰতনে এটা আলমাৰি 6,250 টকাত কিনি 24% লোকচানত বিক্ৰী কৰিলে । আলমাৰিটোৰ বিক্ৰীৰ মূল্য কিমান?)
Solution:
Given,
Cost Price = ₹ 6,250
Loss % = 24
We know that,
Selling Price = Cost Price`\times\left(1-\frac{Loss%}{100}\right)`
`=6,250\times\left(1-\frac{24}{100}\right)`
`=6,250\times\left(1-0.24\right)`
= ₹ 4,750
The selling price of the almirah is ₹4,750
8. Determine the interest of ₹ 5000 at 8% rate of interest per annum for 3 years.
(শতকৰা বছৰি 8 টকা সুতত 5000 টকাৰ বছৰৰ সুত নিৰ্নয় কৰা?)
Solution:
Given,
Principal (P) = ₹ 5,000
Rate of Interest (R) = 8%
Time (T) = 3 Years
We know that,
Simple Interest (SI) `=\frac{P\times R\times T}{100}`
`=\frac{5,000\times8\times3}{100}`
`= 1,200`
The simple interest is ₹1,200.
9. Dalimi pays ₹ 120 as interest for one year at a rate of interest of 5%. How much money did she borrow ?
( ডালিমীয়ে এবছৰৰ বাবে বছৰি 5% হাৰত 120 টকা সুতত দিয়ে। তেওঁ কিমান টকা ধাৰত ল'লে।)
Solution:
Given,
Simple Interest (SI) = ₹120
Rate of Interest (R) = 5%
Time (T) = 1 Year
We know that,
`P=\frac{SI\times100}{R\times T}`
`P=\frac{120\times100}{5\times1}`
`P=\frac{12000}{5}`
P = ₹ 2,400
Dalimi borrowed ₹2,400.
10. Find out the interest of ₹ 1,25,000 at 10% rate of interest for a period of 1 year and 6 months.
(1,25,000 টকাৰ 10% সুতৰ 1 বছৰ 6 মাহৰ সুত উলিওৱা?)
Solution:
Given,
Principal (P) = ₹ 1,25,000
Rate of Interest (R) = 10%
Time (T) = 1 Year and 6 months = 1.5 years
We know that,
Simple Interest (SI)`=\frac{P\times R\times T}{100}`
`=\frac{1,25,000\times10\times1.5}{100}`
`=\frac{18,75,000}{100}`
`= 18,750`
The simple interest is ₹18,750.
11.Find out the interest and total amount of ₹ 1500 at rate of interest of ₹ 12 per annum for 2 years and 9 months.
(শতকৰা বছৰি 12 টকা সুতত 1,500 টকাৰ 2 বছৰ 9 মাহৰ সুত আৰু সবৃদ্বি মূল উলিওৱা?)
Solution:
Given,
Principal (P) = ₹ 1,500
Rate of Interest (R) = 12%
Time (T) = 2 Year and 9 months = 2.75 years
We know that,
Simple Interest (SI) `=\frac{P\times R\times T}{100}`
`=\frac{1,500\times12\times2.75}{100}`
`=\frac{49,500}{100}`
`= 495`
And
Total Amount = Principal +SI
= 1,500+495
= ₹ 1,995
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