Assam SCERT Solutions for Class 7 Maths Chapter 2 Fractions and Decimals Exercise 2.5

Free Solutions for The Assam State School Education Board (ASSEB) Class 7 Maths Chapter 2 Exercise 2.5 in English Medium

Class 7 Maths Chapter 2 Assam SCERT Solutions: Fractions and Decimals Exercise 2.5 For SCERT Assam Class 7 Maths Chapter 2-Fractions and Decimals (Exercise 2.5), are you looking for precise and understandable answers? 📖✅ At Digital Pipal Academy, we offer detailed answers to help you understand crucial ideas. By concentrating on fraction and decimal division, this exercise guarantees that you develop a solid foundation in mathematical operations 🔹 Important Concepts Discussed: ✔ Fraction Division ✔ Fraction Reciprocal ✔ Decimal Division Get the full solutions right now! 📚✨

 

Class 7 General Mathematics - Chapter 2: Fraction and Decimal

SCERT Solution for Class 7 Maths Chapter 2 Fractions and Decimals

Chapter Name	Solution Link
Exercise 2.1	Click Here
Exercise 2.2	Click Here
Exercise 2.3	Click Here
Exercise 2.4	Click Here
Exercise 2.5	Click Here

 

Exercise 2.5

1. Find the Quotient:

(i) 0 .6 ÷ 2

(ii) 0.24 ÷ 3

(iii) 2.75 ÷ 5

(iv) 107.52 ÷ 7

(v) 66.33 ÷ 11

(vi) 3.96÷4

(vii) 14 .49 ÷ 7

(viii) 86 .1 ÷ 3

Solution:

(i) $0.6 \div 2 = \mathbf{0.3}$

(ii) $0.24 \div 3 = \mathbf{0.08}$

(iii) $2.75 \div 5 = \mathbf{0.55}$

(iv) $107.52 \div 7 = \mathbf{15.36}$

(v) $66.33 \div 11 = \mathbf{6.03}$

(vi) $3.96 \div 4 = \mathbf{0.99}$

(vii) $14.49 \div 7 = \mathbf{2.07}$

(viii) $86.1 \div 3 = \mathbf{28.7}$

2. Evaluate:

(i) 0. 9 ÷10

 (ii) 21. 4 ÷ 10

 (iii) 0. 52 ÷ 10

(iv) 521.1 ÷ 10

 (v) 236 .75 ÷10

 (vi) 527. 33 ÷ 100

(vii) 123. 7 ÷100

 (viii) 0.01÷ 100

(ix) 1.482 ÷ 100

(x) 0.7 ÷1000

(xi) 2.1 ÷1000

 (xii) 224.21 ÷1000

 (xiii) 0.06 + 1000

(xiv) 1113.05 ÷1000

 (xv) 8411.27÷ 1000

(xvi) 84.50 ÷ 1000

Solution:

(i) $0.9 \div 10 = \mathbf{0.09}$

(ii) $21.4 \div 10 = \mathbf{2.14}$

(iii) $0.52 \div 10 = \mathbf{0.052}$

(iv) $521.1 \div 10 = \mathbf{52.11}$

(v) $236.75 \div 10 = \mathbf{23.675}$

(vi) $527.33 \div 100 = \mathbf{5.2733}$

(vii) $123.7 \div 100 = \mathbf{1.237}$

(viii) $0.01 \div 100 = \mathbf{0.0001}$

(ix) $1.482 \div 100 = \mathbf{0.01482}$

(x) $0.7 \div 1000 = \mathbf{0.0007}$

(xi) $2.1 \div 1000 = \mathbf{0.0021}$

(xii) $224.21 \div 1000 = \mathbf{0.22421}$

(xiii) $0.06 \div 1000 = \mathbf{0.00006}$

(xiv) $1113.05 \div 1000 = \mathbf{1.11305}$

(xv) $8411.27 \div 1000 = \mathbf{8.41127}$

(xvi) $84.50 \div 1000 = \mathbf{0.0845}$

3. Find the Quotient:

(i) 0. 5 ÷ 0. 25

(ii) 8. 64 ÷0.2

(iii) 32.94 ÷0.4

(iv) 329.4÷ 0.04

(v) 76.5 ÷ 0.15

(vi) 48.56 ÷ 3.2

(vii) 841.26 ÷0.3

(viii) 0.25 ÷0.5

Solution:

(i) $0.5 \div 0.25 = \mathbf{2}$

(ii) $8.64 \div 0.2 = \mathbf{43.2}$

(iii) $32.94 \div 0.4 = \mathbf{82.35}$

(iv) $329.4 \div 0.04 = \mathbf{8235}$

(v) $76.5 \div 0.15 = \mathbf{510}$

(vi) $48.56 \div 3.2 = \mathbf{15.175}$

(vii) $841.26 \div 0.3 = \mathbf{2804.2}$

(viii) $0.25 \div 0.5 = \mathbf{0.5}$

 

Question 4. If the cost of 5.5 m cloth is Rs. 547.25, what is the cost of 1m cloth?

Solution:

The cost of 5.5 meters of cloth = Rs. 547.25

The cost per meter = $547.25 \div 5.5$ = Rs. 99.50

Thus, the cost of 1 meter of cloth is Rs. 99.50. ✅

 

Question 5. A vehicle covers a distance of 150.5 km in 3.5 hours, How far vehicle will cover in 1 hour?

Solution:

A vehicle covers a distance of 150.5 km in 3.5 hours.

The distance covered in 1 hour = $150.5 \div 3.5$ = 43 km

Thus, the vehicle's speed is 43 km/h. ✅

 

Question 6. Whole sale price of potato 10kg is Rs. 186.50. What is the price of 1 kg of potato?

Solution:

The wholesale price of 10 kg of potatoes = Rs. 186.50

The price per kg of potatoes = $186.50 \div 10$ = Rs. 18.65

Thus, the price of 1 kg of potatoes is Rs. 18.65. ✅

 

Question 7. Perimeter of a square shaped vegetable garden is 76.8m. What is the length of a side of the vegetable garden?

Solution:

The perimeter of a square-shaped vegetable garden = 76.8 m

The formula for the perimeter of a square is:

$$\text{Perimeter} = 4 \times \text{Side}$$

To find the length of one side, divide the perimeter by 4:

$$\text{Side} = \frac{76.8}{4}$$ $$= 19.2 \, \text{m}$$

Thus, the length of one side of the vegetable garden is 19.2 m. ✅

 

Question 8. Breadth of a conference hall is 5.5 m and its area is 74.25 square metre (m²). What is the length of the conference hall?

Solution:

Given:
The breadth of the conference hall is 5.5 m, and its area is 74.25 m².

The formula for the area of a rectangle is:

$$\text{Area} = \text{Length} \times \text{Breadth}$$

To find the length, divide the area by the breadth:

$$\text{Length} = \frac{74.25}{5.5} = 13.5 \, \text{m}$$

Thus, the length of the conference hall is 13.5 m. ✅

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