Assam SCERT Solutions for Class 7 Maths Chapter 3 Data Handling Exercise 3.2

Free Solutions for The Assam State School Education Board (ASSEB) Class 7 Maths Chapter 2 Exercise 3.2 in English Medium

SCERT Assam Class 7 Maths Chapter 3 Data Handling Solutions (2025-26)

Students can now access SCERT Assam Solutions for Class 7 Maths Chapter 3 – Data Handling (English Medium), designed as per the latest syllabus for the 2025-26 academic session. These solutions, prepared by subject experts at Digital Pipal Academy, help students grasp key mathematical concepts and develop strong analytical skills.

In this chapter, students will learn how to collect, organize, and interpret data using various techniques such as:
✔ Organizing data into tables and charts
✔ Understanding mean, median, and mode
✔ Drawing and interpreting bar graphs and pie charts
✔ Introduction to probability

Key Features of SCERT Assam Class 7 Maths Solutions:

✔ Practice online for better conceptual clarity.
✔ Download free PDF solutions for offline study.
✔ Solve a variety of questions to boost confidence and score higher marks.

SCERT Assam Maths Class 7 Chapter 3 – Data Handling (English Medium)

Click on the Exercise-wise links below to practice the Maths solutions for each exercise:

SCERT Assam Class 7 Maths Chapter 3 Solutions

Exercise	Solution Link
Exercise 3.1	Click Here
Exercise 3.2	Click Here
Exercise 3.3	Click Here
Exercise 3.4	Click Here

 

 

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NCERT Solutions for Class 7 Mathematics
Chapter 3: Data Handling

Data Handling Exercise 3.2

 

Question 1. Find the mode from the given data:

(i) 2, 2, 3, 3, 4, 4, 5, 5, 5, 6, 6, 7, 7
Solution: Mode = 5 (as it appears the most times)

(ii) 41, 43, 41, 46, 47, 48, 41, 49, 49
Solution: Mode = 41

Question 2. Find the mode of the marks obtained (out of 20) in a test:

Number of students	3	3	4	7	4	2
Marks obtained	10	11	12	13	14	15

Solution: Mode = 13 (as it appears the most times)

Question 3. Find the median of the given data:

(i) 2, 0, 1, 5, 3, 4, 6, 8, 12, 9, 10
Solution: After arranging in ascending order: 0, 1, 2, 3, 4, (5), 6, 8, 9, 10, 12
Median = 5

(ii) 9, 7, 8, 11, 12, 9, 5, 8, 12, 10, 9
Solution: After arranging: 5, 7, 8, 8, 9, (9), 10, 11, 12, 12
Median = 9

Question 4. Find the mode and median of the given marks:

Marks: 28, 32, 35, 21, 27, 35, 27, 42, 35, 22, 23, 35, 25, 23, 40, 24, 31
Solution: After arranging: 21, 22, 23, 23, 24, 25, 27, 27, 28, 31, 32, 35, 35, 35, 35, 40, 42
Mode = 35, Median = 28

Question 5. Find mode and median of the given data. Are these two values same?

Numbers: 13, 16, 12, 14, 19, 12, 14, 13, 14
Solution: After arranging: 12, 12, 13, 13, 14, 14, 14, 16, 19
Mode = 14, Median = 14

Question 6. Ages (in years) of 13 students of a class are as given below:

Find arithmetic mean, mode, and median from the given data:

Ages: 14, 14, 15, 14, 14, 14, 15, 14, 14, 15, 15, 14, 14
Solution:

• Mean = 14.30
• Mode = 14
• Median = 14

Question 7. Complete the table:

Number	Range	Arithmetic Mean	Mode	Median
35, 15, 0, 40, 20, 25, 45, 10, 30, 5, 15	?	?	?	?

Solution:

Given Numbers:
35, 15, 0, 40, 20, 25, 45, 10, 30, 5, 15

Range Calculation:

$$\text{Range} = \text{Maximum value} - \text{Minimum value}$$ $$= 45 - 0 = 45$$

Arithmetic Mean Calculation:

$$\text{Arithmetic Mean} = \frac{\text{Sum of values}}{\text{Total numbers}}$$

Sum of numbers:

$$35 + 15 + 0 + 40 + 20 + 25 + 45 + 10 + 30 + 5 + 15 = 240$$ $$\text{Mean} = \frac{240}{11} = 21.82$$

Mode Calculation:
Mode is the most frequently occurring number.
Here, 15 appears twice, while all other numbers appear only once.

$$\text{Mode} = 15$$

Median Calculation:
Arrange the numbers in ascending order:

$$0, 5, 10, 15, 15, 20, 25, 30, 35, 40, 45$$

Since there are 11 numbers, the median is the 6th number in the ordered list:

$$\text{Median} = 20$$

Final Answer:

Number	Range	Arithmetic Mean	Mode	Median
35, 15, 0, 40, 20, 25, 45, 10, 30, 5, 15	45	21.82	15	20

Question 8. Mention if the following statements are true or false:

(i) Mode always lies in the middle of any data.

(ii) Arithmetic mean always lies in the middle of any data.

(iii) Median always lies in the middle of any data.

Solution: (i) True; (ii) False, (iii) True.

Question 9. Find arithmetic mean, mode and median from the data given below:

(i) 8, 8, 8, 8, 18, 18, 18, 18, 18

(ii) 3, 10, 10, 12, 14, 16, 16, 18, 18, 25, 28

(iii) 23, 2, 42, 6, 36, 11, 29, 9, 15

Solution:

(i) Data: 8, 8, 8, 8, 18, 18, 18, 18, 18

Arithmetic Mean

$$\text{Mean} = \frac{(8+8+8+8+18+18+18+18+18)}{9} = \frac{122}{9} \approx 13.56$$

Mode
The most frequent value is 18 (appears 5 times).
Mode = 18

Median
The data is already arranged in ascending order. The middle value (5th term) is 18.
Median = 18

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(ii) Data: 3, 10, 10, 12, 14, 16, 16, 18, 18, 25, 28

Arithmetic Mean

$$\text{Mean} = \frac{(3+10+10+12+14+16+16+18+18+25+28)}{11} = \frac{170}{11} \approx 15.45$$

Mode
The most frequent values are 10, 16, and 18 (each appears twice). Since there is no single most frequent number, the data is bimodal or trimodal.
Mode = 10, 16, 18 (No unique mode)

Median
The data is already arranged. Since n = 11 (odd), the median is the 6th term, which is 16.
Median = 16

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(iii) Data: 23, 2, 42, 6, 36, 11, 29, 9, 15

(Arranged in ascending order: 2, 6, 9, 11, 15, 23, 29, 36, 42)

Arithmetic Mean

$$\text{Mean} = \frac{(2+6+9+11+15+23+29+36+42)}{9} = \frac{173}{9} \approx 19.22$$

Mode
Each value appears only once, so there is no mode.
Mode = No mode

Median
Since n = 9 (odd), the median is the 5th term, which is 15.
Median = 15

(i) 8, 8, 8, 8, 18, 18, 18, 18, 18
Mean = 13.55, Mode = 18, Median = 18

(ii) 3, 10, 10, 12, 14, 16, 16, 18, 18, 25, 28
Mean = 15.45, Mode = 10, 16, 18, Median = 16

(iii) 23, 2, 42, 6, 36, 11, 29, 9, 15
Mean = 19.22, No mode, Median = 15

 

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