Assam SCERT Solutions for Class 7 Maths Chapter 4 Simple Equation – Exercise 4.2 (2025-26) | Download Free PDF
Students can now access SCERT Assam Solutions for Class 7 Maths Chapter 4 – Simple Equation (Exercise 4.2, English Medium), designed as per the latest syllabus for the 2025-26 academic session. These solutions, prepared by subject experts at Digital Pipal Academy, help students develop a strong understanding of solving equations systematically.
Topics Covered in Exercise 4.2:
✔ Solving
simple equations using transposition and inverse operations
✔ Understanding
variables and constants in algebraic expressions
✔ Applying equations
to real-world problems
Key Features of SCERT Assam Class 7 Maths Solutions:
✔ Step-by-step
solutions for better clarity
✔ Practice online to
strengthen conceptual understanding
✔ Download free PDF
for offline study
✔ Exercise-wise
solutions to help students score better marks
SCERT Assam Class 7 Maths Chapter 4 Simple Equation – Exercise 4.2
Click on the link below to access detailed solutions for Simple Equation:
SCERT Assam Class 7 Maths Chapter 4 Solutions
Exercise | Solution Link |
---|---|
Exercise 4.1 | Click Here |
Exercise 4.2 | Click Here |
Exercise 4.3 | Click Here |
Master Simple Equations with Digital Pipal Academy and boost your exam preparation!
1. Solve the equation and write down the step while separating the variable.
(i) x + 5 = 12
Subtract 5 from both sides:
x + 5 - 5 = 12 - 5
x = 7
(ii) x - 7 = 0
Add 7 to both sides:
x - 7 + 7 = 0 + 7
x = 7
(iii) y - 3 = 6
Add 3 to both sides:
y - 3 + 3 = 6 + 3
y = 9
(iv) z + 6 = -5
Subtract 6 from both sides:
z + 6 - 6 = -5 - 6
z = -11
(v) 3x = 42
Divide both sides by 3:
`\frac{3x}{3}=\frac{42}{3}`
x = 14
(vi) `\frac{x}{5}=6`
Multiply both sides by 5:
`\frac{x}{5}\times 5=6\times5`
x = 30
(vii) `12x = -36`
Divide both sides by 12:
`\frac{12x}{12}=\frac{-36}{12}`
x = -3
(viii) `\frac{x}{4}=\frac{3}{5}`
Multiply both sides by 4:
`\frac{x}{4}\times4=\frac{3}{5}\times4`
`x=\frac{12}{5}`
(ix) 7x = 35
Divide both sides by 7:
`\frac{7x}{7}=\frac{35}{7}`
x = 5
(x) `\frac{p}{4}=3`
Multiply both sides by 4:
`\frac{p}{4}\times4=3\times4`
p = 12
2. Solve the equation and write down the step while separating the variable.
(i) 4x + 5 = 45
Subtract 5 from both sides:
4x + 5 - 5 = 45 - 5
4x = 40
Divide both sides by 4:
`\frac{4x}{4}=\frac{40}{4}`
x = 10
(ii) 3x - 7 = 11
Add 7 to both sides:
3x - 7 + 7 = 11 + 7
3x = 18
Divide both sides by 3:
`\frac{3x}{3}=\frac{18}{3}`
x = 6
(iii) `\frac{2x}{3}+5=7`
Subtract 5 from both sides:
`\frac{2x}{3}+5-5=7-5`
`\frac{2x}{3}=2`
Multiply both sides by `\frac{3}{2}`:
`\frac{2x}{3}\times\frac{3}{2}=2\times\frac{3}{2}`
x = 3
(iv) `\frac{4y}{3}-7=5`
Add 7 to both sides:
`\frac{4y}{3}-7+7=5+7`
`\frac{4y}{3}=12`
Multiply both sides by `\frac{3}{4}`:
`\frac{4y}{3}\times\frac{3}{4}=12\times\frac{3}{4}`
y = 9
3. Solve the following equations:
(i) 4x = 64
Divide both sides by 4:
`\frac{4x}{4}=\frac{64}{4}`
x = 16
(ii) 4x + 7 = 15
Subtract 7 from both sides:
4x + 7 - 7 = 15 - 7
4x = 8
Divide both sides by 4:
`\frac{4x}{4}=\frac{8}{4}`
x = 2
(iii) `\frac{y}{4}=6`
Multiply both sides by 4:
`\frac{y}{4}\times4=6\times4`
y = 24
(iv) 3y = 60
Divide both sides by 3:
`\frac{3y}{3}=\frac{60}{3}`
y = 20
(v) 6p + 7 = 37
Subtract 7 from both sides:
6p + 7 - 7 = 37 - 7
6p = 30
Divide both sides by 6:
`\frac{6p}{6}=\frac{30}{6}`
p = 5
(vi) 7p - 9 = 5
Add 9 to both sides:
7p - 9 + 9 = 5 + 9
7p = 14
Divide both sides by 7:
`\frac{7p}{7}=\frac{14}{7}`
p = 2
(vii) 5x - 7 = 8
Add 7 to both sides:
5x - 7 + 7 = 8 + 7
5x = 15
Divide both sides by 5:
`\frac{5x}{5}=\frac{15}{5}`
x = 3
(viii) `\frac{x}{5}+2=3`
Subtract 2 from both sides:
`\frac{x}{5}+2-2=3-2`
`\frac{x}{5}=1`
Multiply both sides by 5:
`\frac{x}{5}\times5=1\times5`
x = 5
(ix) `\frac{q}{3}-1=2`
Add 1 to both sides:
`\frac{q}{3}-1+1=2+1`
`\frac{q}{3}=3`
Multiply both sides by 3:
`\frac{q}{3}\times3=3\times3`
q = 9
(x) 3x + 11 = 50
Subtract 11 from both sides:
3x + 11 - 11 = 50 - 11
3x = 39
Divide both sides by 3:
`\frac{3x}{3}=\frac{39}{3}`
x = 13
(xi) 4x + 10 = 26
Subtract 10 from both sides:
4x + 10 - 10 = 26 - 10
4x = 16
Divide both sides by 4:
`\frac{4x}{4}=\frac{16}{4}`
x = 4
(xii) `\frac{x}{3}+4=6`
Subtract 4 from both sides:
`\frac{x}{3}+4-4=6-4`
`\frac{x}{3}=2`
Multiply both sides by 3:
`\frac{x}{3}\times3=2\times3`
x = 6
(xiii) `\frac{p}{3}+5=12`
Subtract 5 from both sides:
`\frac{p}{3}+5-5=12-5`
`\frac{p}{3}=7`
Multiply both sides by 3:
`\frac{p}{3}\times3=7\times3`
p = 21
(xiv) `\frac{q}{2}+4=7`
Subtract 4 from both sides:
`\frac{q}{2}+4-4=7-4`
`\frac{q}{2}=3`
Multiply both sides by 2:
`\frac{q}{2}\times2=3\times2`
q = 6
(xv) 2(x + 3) = x + 7
Distribute the 2 on the left side:
2x + 6 = x + 7
Subtract x from both sides:
2x + 6 - x = x + 7 - x
x + 6 = 7
Subtract 6 from both sides:
x + 6 - 6 = 7 - 6
x = 1
10 Additional Questions for Exercise 4.2
Q. Solve the following equations:
1. 5x - 12 = 3
2. 2x + 7 = 15
3. 3y - 8 = 10
4. 4z + 5 = 21
5. 6p - 13 = 17
6. 7q + 8 = 30
7. 8r - 11 = 23
8. 9s + 12 = 45
9. 10t - 7 = 33
10. 11u + 15 = 57
20 MCQ Questions
1. The solution to the equation 2x + 3 = 7 is:
(a) 1
(b) 2
(c) 3
(d) 4
2. The solution to the equation 3y - 5 = 10 is:
(a) 3
(b) 4
(c) 5
(d) 6
3. The solution to the equation 4z + 7 = 19 is:
(a) 2
(b) 3
(c) 4
(d) 5
4. The solution to the equation 5p - 12 = 8 is:
(a) 3
(b) 4
(c) 5
(d) 6
5. The solution to the equation 6q + 11 = 35 is:
(a) 3
(b) 4
(c) 5
(d) 6
6. The solution to the equation 7r - 15 = 16 is:
(a) 3
(b) 4
(c) 5
(d) 6
7. The solution to the equation 8s + 9 = 41 is:
(a) 3
(b) 4
(c) 5
(d) 6
8. The solution to the equation 9t - 13 = 25 is:
(a) 3
(b) 4
(c) 5
(d) 6
9. The solution to the equation 10u + 17 = 47 is:
(a) 3
(b) 4
(c) 5
(d) 6
10. The solution to the equation 11v - 22 = 33 is:
(a) 3
(b) 4
(c) 5
(d) 6
11. The solution to the equation 12w + 25 = 53 is:
(a) 2
(b) 3
(c) 4
(d) 5
12. The solution to the equation 13x - 30 = 26 is:
(a) 4
(b) 5
(c) 6
(d) 7
13. The solution to the equation 14y - 37 = 41 is:
(a) 5
(b) 6
(c) 7
(d) 8
14. The solution to the equation 15z - 42 = 53 is:
(a) 6
(b) 7
(c) 8
(d) 9
15. The solution to the equation 16p - 49 = 63 is:
(a) 7
(b) 8
(c) 9
(d) 10
16. The solution to the equation 17q - 56 = 71 is:
(a) 8
(b) 9
(c) 10
(d) 11
17. The solution to the equation 18r - 65 = 83 is:
(a) 9
(b) 10
(c) 11
(d) 12
18. The solution to the equation 19s - 74 = 95 is:
(a) 10
(b) 11
(c) 12
(d) 13
19. The solution to the equation 20t - 83 = 107 is:
(a) 11
(b) 12
(c) 13
(d) 14
20. The solution to the equation 21u - 92 = 119 is:
(a) 12
(b) 13
(c) 14
(d) 15
Filed Under: Digital Pipal Academy Solution
Tagged With:
SCERT Assam Class 7 Mathematics Solutions, Assam Board Class 7 Maths, Class 7 Simple Equation SCERT Solutions, Class 7 Maths Solutions, Simple Equation Exercise 4.2, Free Class 7 Maths Solutions, Free SCERT Solutions, SCERT Books Solution, SCERT Assam Class 7 Maths Solutions, SCERT Assam Solutions, SCERT Class 7 Maths Solutions, SCERT Solutions, SCERT Solutions For Class 7 Maths Simple Equation Exercise 4.2, SCERT Solutions For Class 7 Maths, SCERT Solutions For Class 7 Maths Chapter 4.

About the Publisher
Hi! I'm Sudev Chandra Das (B.Sc. Mathematics), the Founder of Digital Pipal Academy. I've dedicated myself to guiding students toward better education. I believe, 'Success comes from preparation, hard work, and learning from failure.' Let’s embark on a journey of growth and digital excellence together!