Assam SCERT Solutions for Class 7 Maths Chapter 4 Simple Equation Exercise 4.2

Sudev Chandra Das

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Free Solutions for The Assam State School Education Board (ASSEB) Class 7 Maths Chapter 4 Exercise 4.2 in English Medium

Assam SCERT Solutions for Class 7 Maths Chapter 4 Simple Equation – Exercise 4.2 (2025-26) | Download Free PDF

Students can now access SCERT Assam Solutions for Class 7 Maths Chapter 4 – Simple Equation (Exercise 4.2, English Medium), designed as per the latest syllabus for the 2025-26 academic session. These solutions, prepared by subject experts at Digital Pipal Academy, help students develop a strong understanding of solving equations systematically.

Topics Covered in Exercise 4.2:

Solving simple equations using transposition and inverse operations
Understanding variables and constants in algebraic expressions
Applying equations to real-world problems

Key Features of SCERT Assam Class 7 Maths Solutions:

Step-by-step solutions for better clarity
Practice online to strengthen conceptual understanding
Download free PDF for offline study
Exercise-wise solutions to help students score better marks

SCERT Assam Class 7 Maths Chapter 4 Simple Equation – Exercise 4.2

Click on the link below to access detailed solutions for Simple Equation:

SCERT Assam Class 7 Maths Chapter 4 Solutions

SCERT Assam Class 7 Maths Chapter 4 Solutions

Exercise Solution Link
Exercise 4.1 Click Here
Exercise 4.2 Click Here
Exercise 4.3 Click Here

 

 

Master Simple Equations with Digital Pipal Academy and boost your exam preparation!

 

1. Solve the equation and write down the step while separating the variable.

(i) x + 5 = 12

    Subtract 5 from both sides:

      x + 5 - 5 = 12 - 5

      x = 7

(ii) x - 7 = 0

    Add 7 to both sides:

      x - 7 + 7 = 0 + 7

      x = 7

(iii) y - 3 = 6

    Add 3 to both sides:

      y - 3 + 3 = 6 + 3

      y = 9

(iv) z + 6 = -5

    Subtract 6 from both sides:

      z + 6 - 6 = -5 - 6

      z = -11

(v) 3x = 42

    Divide both sides by 3:

      `\frac{3x}{3}=\frac{42}{3}`

      x = 14

(vi) `\frac{x}{5}=6`

    Multiply both sides by 5:

      `\frac{x}{5}\times 5=6\times5`

      x = 30

(vii) `12x = -36`

    Divide both sides by 12:

      `\frac{12x}{12}=\frac{-36}{12}`

      x = -3

(viii) `\frac{x}{4}=\frac{3}{5}`

    Multiply both sides by 4:

      `\frac{x}{4}\times4=\frac{3}{5}\times4`

      `x=\frac{12}{5}`

(ix) 7x = 35

    Divide both sides by 7:

     `\frac{7x}{7}=\frac{35}{7}`

      x = 5

(x) `\frac{p}{4}=3`

    Multiply both sides by 4:

      `\frac{p}{4}\times4=3\times4`

      p = 12

2. Solve the equation and write down the step while separating the variable.

(i) 4x + 5 = 45

   Subtract 5 from both sides:

     4x + 5 - 5 = 45 - 5

     4x = 40

   Divide both sides by 4:

     `\frac{4x}{4}=\frac{40}{4}`

     x = 10

(ii) 3x - 7 = 11

   Add 7 to both sides:

     3x - 7 + 7 = 11 + 7

     3x = 18

   Divide both sides by 3:

    `\frac{3x}{3}=\frac{18}{3}`

     x = 6

(iii) `\frac{2x}{3}+5=7`

   Subtract 5 from both sides:

     `\frac{2x}{3}+5-5=7-5`

     `\frac{2x}{3}=2`

   Multiply both sides by `\frac{3}{2}`:

     `\frac{2x}{3}\times\frac{3}{2}=2\times\frac{3}{2}`

     x = 3

(iv) `\frac{4y}{3}-7=5`

   Add 7 to both sides:

     `\frac{4y}{3}-7+7=5+7`

     `\frac{4y}{3}=12`

   Multiply both sides by `\frac{3}{4}`:

     `\frac{4y}{3}\times\frac{3}{4}=12\times\frac{3}{4}`

     y = 9

3. Solve the following equations:

(i) 4x = 64

   Divide both sides by 4:

     `\frac{4x}{4}=\frac{64}{4}`

     x = 16

(ii) 4x + 7 = 15

   Subtract 7 from both sides:

     4x + 7 - 7 = 15 - 7

     4x = 8

   Divide both sides by 4:

     `\frac{4x}{4}=\frac{8}{4}`

     x = 2

(iii) `\frac{y}{4}=6`

   Multiply both sides by 4:

    `\frac{y}{4}\times4=6\times4`

     y = 24

(iv) 3y = 60

   Divide both sides by 3:

     `\frac{3y}{3}=\frac{60}{3}`

     y = 20

(v) 6p + 7 = 37

   Subtract 7 from both sides:

     6p + 7 - 7 = 37 - 7

     6p = 30

   Divide both sides by 6:

     `\frac{6p}{6}=\frac{30}{6}`

     p = 5

(vi) 7p - 9 = 5

   Add 9 to both sides:

     7p - 9 + 9 = 5 + 9

     7p = 14

   Divide both sides by 7:

    `\frac{7p}{7}=\frac{14}{7}`

     p = 2

(vii) 5x - 7 = 8

   Add 7 to both sides:

     5x - 7 + 7 = 8 + 7

     5x = 15

   Divide both sides by 5:

     `\frac{5x}{5}=\frac{15}{5}`

     x = 3

(viii) `\frac{x}{5}+2=3`

   Subtract 2 from both sides:

    `\frac{x}{5}+2-2=3-2`

    `\frac{x}{5}=1`

   Multiply both sides by 5:

     `\frac{x}{5}\times5=1\times5`

     x = 5

(ix) `\frac{q}{3}-1=2`

   Add 1 to both sides:

    `\frac{q}{3}-1+1=2+1`

     `\frac{q}{3}=3`

   Multiply both sides by 3:

     `\frac{q}{3}\times3=3\times3`

     q = 9

(x) 3x + 11 = 50

   Subtract 11 from both sides:

     3x + 11 - 11 = 50 - 11

     3x = 39

   Divide both sides by 3:

     `\frac{3x}{3}=\frac{39}{3}`

     x = 13

(xi) 4x + 10 = 26

   Subtract 10 from both sides:

     4x + 10 - 10 = 26 - 10

     4x = 16

   Divide both sides by 4:

     `\frac{4x}{4}=\frac{16}{4}`

     x = 4

(xii) `\frac{x}{3}+4=6`

   Subtract 4 from both sides:

     `\frac{x}{3}+4-4=6-4`

    `\frac{x}{3}=2`

   Multiply both sides by 3:

     `\frac{x}{3}\times3=2\times3`

     x = 6

(xiii) `\frac{p}{3}+5=12`

   Subtract 5 from both sides:

     `\frac{p}{3}+5-5=12-5`

     `\frac{p}{3}=7`

   Multiply both sides by 3:

     `\frac{p}{3}\times3=7\times3`

     p = 21

(xiv) `\frac{q}{2}+4=7`

   Subtract 4 from both sides:

   `\frac{q}{2}+4-4=7-4`

     `\frac{q}{2}=3`

   Multiply both sides by 2:

     `\frac{q}{2}\times2=3\times2`

     q = 6

(xv) 2(x + 3) = x + 7

   Distribute the 2 on the left side:

     2x + 6 = x + 7

   Subtract x from both sides:

     2x + 6 - x = x + 7 - x

     x + 6 = 7

   Subtract 6 from both sides:

     x + 6 - 6 = 7 - 6

     x = 1

 

10 Additional Questions for Exercise 4.2

Q. Solve the following equations:

1. 5x - 12 = 3

2. 2x + 7 = 15

3. 3y - 8 = 10

4. 4z + 5 = 21

5. 6p - 13 = 17

6. 7q + 8 = 30

7. 8r - 11 = 23

8. 9s + 12 = 45

9. 10t - 7 = 33

10. 11u + 15 = 57

20 MCQ Questions

1. The solution to the equation 2x + 3 = 7 is:

   (a) 1

   (b) 2

   (c) 3

   (d) 4

2. The solution to the equation 3y - 5 = 10 is:

   (a) 3

   (b) 4

   (c) 5

   (d) 6

3. The solution to the equation 4z + 7 = 19 is:

   (a) 2

   (b) 3

   (c) 4

   (d) 5

4. The solution to the equation 5p - 12 = 8 is:

   (a) 3

   (b) 4

   (c) 5

   (d) 6

5. The solution to the equation 6q + 11 = 35 is:

   (a) 3

   (b) 4

   (c) 5

   (d) 6

6. The solution to the equation 7r - 15 = 16 is:

   (a) 3

   (b) 4

   (c) 5

   (d) 6

7. The solution to the equation 8s + 9 = 41 is:

   (a) 3

   (b) 4

   (c) 5

   (d) 6

8. The solution to the equation 9t - 13 = 25 is:

   (a) 3

   (b) 4

   (c) 5

   (d) 6

9. The solution to the equation 10u + 17 = 47 is:

   (a) 3

   (b) 4

   (c) 5

   (d) 6

10. The solution to the equation 11v - 22 = 33 is:

   (a) 3

   (b) 4

   (c) 5

   (d) 6

11. The solution to the equation 12w + 25 = 53 is:

   (a) 2

   (b) 3

   (c) 4

   (d) 5

12. The solution to the equation 13x - 30 = 26 is:

   (a) 4

   (b) 5

   (c) 6

   (d) 7

13. The solution to the equation 14y - 37 = 41 is:

   (a) 5

   (b) 6

   (c) 7

   (d) 8

14. The solution to the equation 15z - 42 = 53 is:

   (a) 6

   (b) 7

   (c) 8

   (d) 9

15. The solution to the equation 16p - 49 = 63 is:

   (a) 7

   (b) 8

   (c) 9

   (d) 10

16. The solution to the equation 17q - 56 = 71 is:

   (a) 8

   (b) 9

   (c) 10

   (d) 11

17. The solution to the equation 18r - 65 = 83 is:

   (a) 9

   (b) 10

   (c) 11

   (d) 12

18. The solution to the equation 19s - 74 = 95 is:

   (a) 10

   (b) 11

   (c) 12

   (d) 13

19. The solution to the equation 20t - 83 = 107 is:

   (a) 11

   (b) 12

   (c) 13

   (d) 14

20. The solution to the equation 21u - 92 = 119 is:

   (a) 12

   (b) 13

   (c) 14

   (d) 15

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Sudev Chandra Das

About the Publisher

Hi! I'm Sudev Chandra Das (B.Sc. Mathematics), the Founder of Digital Pipal Academy. I've dedicated myself to guiding students toward better education. I believe, 'Success comes from preparation, hard work, and learning from failure.' Let’s embark on a journey of growth and digital excellence together!

 


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